Câu hỏi của Chung Lethikim

\(n_{HCl}=0.2\cdot1=0.2\left(mol\right)\)\(MO+2HCl\rightarrow MCl_2+H_2O\)\(0.1.........0.2\)\(M_{MO}=\dfrac{5.6}{0.1}=56\left(đvc\right)\)\(\Rightarrow M=56-16=40\)\(CT:CaO\)Câu trả lời: \(n_{HCl}=0.2\cdot1=0.2\left(mol\right)\)\(MO+2HCl\rightarrow MCl_2+H_2O\)\(0.1.........0.2\)\(M_{MO}=\dfrac{5.6}{0.1}=56\left(đvc\right)\)\(\Rightarrow M=56-16=40\)\(CT:CaO\)