d, \(\dfrac{x+5}{x^2-5x}-\dfrac{x+25}{2x^2-50}=\dfrac{x-5}{2x^2+10x}\)ĐK : \(x\ne0;\pm5\)
\(\Leftrightarrow\dfrac{x+5}{x\left(x-5\right)}+\dfrac{x+25}{2\left(x-5\right)\left(x+5\right)}=\dfrac{x-5}{2x\left(x+5\right)}\)
\(\Rightarrow2\left(x+5\right)^2+x\left(x+25\right)=\left(x-5\right)^2\)
\(\Leftrightarrow2\left(x^2+10x+25\right)+x^2+25x=x^2-10x+25\)
\(\Leftrightarrow2x^2+20x+50+x^2+25x=x^2-10x+25\)
\(\Leftrightarrow x^2+55x-25=0\Leftrightarrow x=-\dfrac{5\left(11\pm5\sqrt{5}\right)}{2}\)
bạn đăng tách câu ra cho mn làm nhé
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