Lời giải:
a.
\(A=\frac{10(10^{1991}+1)-9}{10^{1991}+1}=10-\frac{9}{10^{1991}+1}\)
\(B=\frac{10(10^{1992}+1)-9}{10^{1992}+1}=10-\frac{9}{10^{1992}+1}\)
Mà: \(\frac{9}{10^{1991}+1}> \frac{9}{10^{1992}+1}\Rightarrow A< B\)
b.
\(10C=\frac{2010^{2009}+1+9}{2010^{2009}+1}=1+\frac{9}{2010^{2009}+1}\)
\(10D=\frac{2010^{2008}+1+9}{2010^{2008}+1}=1+\frac{9}{2010^{2008}+1}\)
Mà: \(\frac{9}{2010^{2009}+1}< \frac{9}{2010^{2008}+1}\Rightarrow \Rightarrow 10C< 10D\Rightarrow C< D\)


