a, đổi \(S=0,3mm^2=3.10^{-7}m^2\)
\(d=3cm=0,03m\)
\(=>l=\pi n.d=\pi.800.0,03=24\pi\left(m\right)\)
\(=>R\left(Max\right)=\dfrac{pl}{S}=\dfrac{0,4.10^{-6}.24\pi}{3.10^{-7}}=32\pi=100,48\left(om\right)\)
b, \(I\left(MAx\right)=\dfrac{U\left(Max\right)}{R\left(Max\right)}=\dfrac{50,24}{100,48}=0,5A\)



