Bài 2 :
\(n_{CO_2}=\dfrac{5.6}{22.4}=0.25\left(mol\right)\)
\(Ca\left(OH\right)_2+CO_2\rightarrow CaCO_3+H_2O\)
\(..............0.25.......0.25\)
\(m_{CaCO_3}=0.25\cdot100=25\left(g\right)\)
Bài 1 :
\(n_{Al_2O_3}=a\left(mol\right),n_{MgO}=b\left(mol\right)\)
\(m_{hh}=102a+40b=26.4\left(g\right)\left(1\right)\)
\(Al_2O_3+3H_2SO_4\rightarrow Al_2\left(SO_4\right)_3+3H_2O\)
\(MgO+H_2SO_4\rightarrow MgSO_4+H_2O\)
\(n_{H_2SO_4}=3a+b=0.75\left(mol\right)\left(2\right)\)
\(\left(1\right),\left(2\right):a=0.2,b=0.15\)
\(m_{Al_2O_3}=0.2\cdot102=20.4\left(g\right)\)
\(m_{MgO}=0.15\cdot40=6\left(g\right)\)
\(C_{M_{Al_2\left(SO_4\right)_3}}=\dfrac{0.2}{0.75}=0.266\left(M\right)\)
\(C_{M_{MgSO_4}}=\dfrac{0.15}{0.75}=0.2\left(M\right)\)
