k mk đi mk k bn rùi đấy

co 2^2016=(2^1008)^2

vi (2^1008)^2>2016^2 nen .............. tu biet roi day

\(\frac{X+3}{2007}-\frac{X+3}{2008}=\frac{X+3}{2015}-\frac{X+3}{2014}\)

\(\frac{X+3}{2007}-\frac{X+3}{2008}-\frac{X+3}{2015}+\frac{X+3}{2014}=0\)

\(\left(X+3\right)\left(\frac{1}{2007}-\frac{1}{2008}-\frac{1}{2015}+\frac{1}{2014}\right)=0\)

MÀ \(\frac{1}{2007}-\frac{1}{2008}-\frac{1}{2015}+\frac{1}{2014}\ne0\)

=> X + 3 = 0

=> X = -3