Câu trả lời:
a) x3+y3+z3-3xyz
= (x+y)3 - 3x2y-3xy2+z2-3xyz
=(x+y+z)[(x+y)2-(x+y)z+z2]-3x(x+y+z)
=(x+y+z)(x2+y2+z2-xy-yz-zx)
b)
=>(a+b+c)3=0
=>a3+b3+c3+3a2b+3ab2+3b2c+3bc2+3a2c+3ac3+6abc=0
=>a3+b3+c3+(3a2b+3ab2+3abc)+(3b2c+3bc2+3abc)+(3a2c+3ac2+3abc)-3abc=0
=>a3+b3+c3+3ab(a+b+c)+3bc(a+b+c)+3ac(a+b+c)=3abc
=>a3+b3+c3=3abc (đpcm)