con điên

số bị trừ + số trừ + hiệu = 1062

=> 2 x số bị trừ = 1062

=> số bị trừ = 531

=> số trừ + hiệu = 531

Số trừ là :

(531 + 279) : 2 = 405

Hiệu là :

531 - 405 = 126

1.

a) A= \(\frac{3}{1.4}\)+\(\frac{3}{4.7}\)+\(\frac{3}{7.10}\)+...+\(\frac{3}{97.100}\)

b) B= \(\frac{1}{2.5}\)+\(\frac{1}{8.11}\)+...+\(\frac{1}{92.95}\)+\(\frac{1}{95.98}\)

2. Tìm STN n

\(\frac{1}{3}\)+\(\frac{1}{6}\)+\(\frac{1}{10}\)+...+\(\frac{2}{n.\left(n+1\right)}\)=\(\frac{1999}{2000}\)

1+ 2+ 3+ 4+ 5+ 6+ 7+ 8 +9 +10+ 11= 1+ 9+ 2+ 8+ 3+ 7+ 4+ 6+ 5+ 10+ 11= 10+ 10+ 10+ 10+ 15+ 11= 40 + 15 + 11= 55+ 11= 66: 11= 6

a) \(\frac{1}{x-1}\)+\(\frac{-2}{3}\)(\(\frac{3}{4}\)-\(\frac{6}{5}\))=\(\frac{5}{2-2x}\)
b) 3-\(\frac{2}{2x-3}\)=\(\frac{2}{5}\)+\(\frac{2}{9-6x}\)-\(\frac{3}{2}\)
c) \(\frac{x}{2}\)-\(\frac{1}{x}\)=\(\frac{1}{12}\)
d) \(^{x^2}\)-\(\frac{7}{6}x\)+\(\frac{1}{3}\)=0
Mik đang cần gấp! Giúp mik với

Write an essay of 200 words about the questions below.

1. What's my English level now compared to the world's standard?

2. How much effort do I have to exert more to prepare myself for the future?

Please help!