Thu gọn đa thức và tìm bậc

A= x²y + \(\dfrac{\text{1}}{\text{3}}\)xy² + \(\dfrac{\text{3}}{\text{5}}\)xy² - 2xy + 3x²y - \(\dfrac{\text{2}}{\text{3}}\)

B= \(\dfrac{\text{9}}{\text{5}}\)xy²z + 2x³y²z + \(\dfrac{\text{1}}{\text{5}}\)xy²z - 2x³y²z - 1

thu gọn đa thức và tìm bậc

3x⁴y² + \(\dfrac{\text{1}}{\text{2}}\) xy⁵ - \(\dfrac{\text{3}}{\text{4}}\) x²y³ - \(\dfrac{\text{1}}{\text{2}}\)x⁴y² + 5xy⁵ - \(\dfrac{\text{1}}{\text{4}}\)x²y³

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