PTPƯ:Zn+H2SO4→ZnSO4+H2

$n{H}_2=\frac{6,72}{22,4}=0,3mol.$

$Theo$ $pt:$ $n{H}_2=nZn=0,3mol.$

$\Rightarrow mZn=0,3.65=19,5g.$

$c,Theo$ $pt:$ $n{H}_2=nZnS{O}_4=0,3mol.$

$\Rightarrow mZnS{O}_4=0,3.161=48,3g.$

1 + 1 = 2

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