\(\left(x^2-5x+3\right)\left(2x^2-5x+1\right)=\left(x^2+5x+3\right)\left(2x^2-5x-1\right)\)

\(\left(x^2-3x+2\right)^3+\left(-x^2+x+1\right)^3+\left(2x-3\right)^3=0\)

\(^{x^4+\left(x-2\right)^4=1}\)

(x\(\left(x^2-5x+1\right)\left(x^2-4\right)=6\left(x-1\right)^2\)

\(\left\{{}\begin{matrix}x^2+y^2+\frac{8xy}{x+y}=16\\\frac{x^2}{8y}+\frac{2x}{3}=\sqrt{\frac{x^3}{3y}+\frac{x^2}{4}}-\frac{y}{2}\end{matrix}\right.\)

\(\left\{{}\begin{matrix}2x+\frac{1}{x+y}=1\\8\left(x^2+y^2\right)+4xy+\frac{5}{\left(x+y\right)^2}=13\end{matrix}\right.\)