mCaCO3 nguyên chất là:500.95/100=475(g)

nCaCO3 nguyên=475/100=4,75(mol)

PTHH: CaCO3---->CaO+CO2

(mol) 4,75

pứ x x x

sau pứ 4,75-x x x

H= x.100%/4,75=80%

=>x=3,8(mol)

mCaO=3,8.56=212,8

nCaCO3 dư=4,75-3,8=0,95

nCaCO3 dư=0,95.100=95

mA=212,8+95=307,8(g)

%mCaO=212,8.100%/307,8=69,14%

nCO2=nCaO=3,8

VCO2=3,8.22,4=85,12(l)