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Bài 34:

\(a.X.\dfrac{1}{2}=\dfrac{1}{3}\)

\(X=\dfrac{1}{3}:\dfrac{1}{2}\)

\(X=\dfrac{2}{3}\)

\(b.X:\dfrac{4}{5}=\dfrac{5}{2}\)

\(X=\dfrac{5}{2}.\dfrac{4}{5}\)

\(X=2\)

\(c.\dfrac{2}{9}:x=\dfrac{2}{3}\)

\(X=\dfrac{2}{9}:\dfrac{2}{3}\)

\(X=\dfrac{1}{3}\)

Bài 33

\(\dfrac{3}{5}.\dfrac{8}{27}.\dfrac{5}{3}=\dfrac{3.8.5}{5.27.3}=\dfrac{8}{27}\)

\(\dfrac{7}{19}.\dfrac{1}{3}+\dfrac{7}{19}.\dfrac{2}{3}=\dfrac{7}{9}.\left(\dfrac{1}{3}+\dfrac{2}{3}\right)=\dfrac{7}{9}.1=\dfrac{7}{9}\)

A vì đồng vị EFD=FAB=53⁰

Hình như đề sai thật ý