HOC24
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Bài học
Cho \(S=\dfrac{1}{2^2}+\dfrac{1}{3^2}+\dfrac{1}{4^2}+...+\dfrac{1}{10^2}.\) Chứng minh rằng: \(S>\dfrac{9}{22}\)
B
Tìm \(x\) biết:
\(a.x=\dfrac{1}{5}+\dfrac{-3}{7}\) \(b.\dfrac{3}{5}-\dfrac{4}{7}\div x=\dfrac{-9}{10}\) \(c.x-\left(\dfrac{-3}{4}\right)=\dfrac{-2}{3}-\dfrac{1}{2}\) \(d.\dfrac{-5}{9}-x=\dfrac{1}{3}+\dfrac{7}{18}\)
Thực hiện các phép tính:
\(a.\dfrac{-5}{9}-\dfrac{-5}{12} \) \(b.\dfrac{-5}{12}:\dfrac{15}{4}\) c. \(\dfrac{1}{13}\) x \(\dfrac{8}{13}\) + \(\dfrac{5}{13}\) x \(\dfrac{1}{13}\) - \(\dfrac{14}{13}\)
Bài 1: Thực hiện các phép tính (Tính nhanh nếu có thể)
a) \(\dfrac{-5}{9}\) - \(\dfrac{-5}{12}\) b) \(\dfrac{-5}{12}\) : \(\dfrac{15}{4}\) c) \(\dfrac{1}{13}\) x \(\dfrac{8}{13}\) + \(\dfrac{5}{13}\) x \(\dfrac{1}{13}\) - \(\dfrac{14}{13}\)
Bài 2: Tìm \(x\), biết:
a) \(x=\dfrac{1}{5}+\dfrac{-3}{7}\) b) \(\dfrac{3}{5}-\dfrac{4}{7}\)\(:\)\(x=\dfrac{-9}{10}\) c) \(x-\left(\dfrac{-3}{4}\right)=\dfrac{-2}{3}-\dfrac{1}{2}\)
d) \(\dfrac{-5}{9}-x=\dfrac{1}{3}+\dfrac{7}{18}\)
Bài 3: Cho S = \(\dfrac{1}{2^2}+\dfrac{1}{3^2}+\dfrac{1}{4^2}+...+\dfrac{1}{10^2}\). Chứng minh rằng: \(S>\dfrac{9}{22}\)