HOC24
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Chủ đề / Chương
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\(=\left(\dfrac{\sqrt{2}\left(\sqrt{6}-\sqrt{3}\right)}{2\left(\sqrt{2}-1\right)}+1\right).\dfrac{\sqrt{6}-2}{\left(\sqrt{6}+2\right)\left(\sqrt{6}-2\right)}\)\(=\left(\dfrac{\left(\sqrt{6}-\sqrt{3}\right)}{\sqrt{2}\left(\sqrt{2}-1\right)}+1\right).\dfrac{\sqrt{6}-2}{6-4}\)\(=\left(\dfrac{\left(\sqrt{6}-\sqrt{3}\right)}{2-\sqrt{2}}+1\right).\dfrac{\sqrt{6}-2}{2}\)\(=\left(\dfrac{\left(\sqrt{6}-\sqrt{3}\right)\left(2+\sqrt{2}\right)}{\left(2-\sqrt{2}\right)\left(2+\sqrt{2}\right)}+1\right).\dfrac{\sqrt{6}-2}{2}\)\(=\left(\dfrac{\sqrt{6}}{4-2}+1\right).\dfrac{\sqrt{6}-2}{2}\)\(=\left(\dfrac{\sqrt{6}}{2}+1\right).\dfrac{\sqrt{6}-2}{2}\)\(=\dfrac{2+\sqrt{6}}{2}.\dfrac{\sqrt{6}-2}{2}=\dfrac{2\sqrt{6}-4+6-2\sqrt{6}}{4}=\dfrac{1}{2}\)
\(x+\dfrac{40}{27}=2\)\(x=\dfrac{14}{27}\)
a)\(=\sqrt{10\left(x+2\right)}=\sqrt{10}.\sqrt{x+2}\)\(\sqrt{x+2}\ge0=>x+2\ge0=>x\ge-2\)b)\(=\dfrac{\sqrt{99}}{\sqrt{4x-1}}\)\(=>4x-1>0=>4x>1=>x>\dfrac{1}{4}\)c)\(=\dfrac{\sqrt{-5x-10}}{\sqrt{2021}}=>-5x-10\ge0\)\(=>-5\left(x+2\right)\ge0\)\(=>x+2\ge0=>x\ge-2\)
a)\(=\dfrac{22}{3}.\dfrac{23}{2}-\dfrac{22}{3}.\dfrac{20}{11}-\dfrac{3}{2}\)\(=\dfrac{22}{3}\left(\dfrac{23}{2}-\dfrac{20}{11}\right)-\dfrac{3}{2}\)\(=\dfrac{22}{3}.\dfrac{213}{22}-\dfrac{3}{2}=71-\dfrac{3}{2}=69,5\)b)\(=\dfrac{10}{17}-\dfrac{5}{13}+\dfrac{7}{17}-\dfrac{8}{13}+\dfrac{11}{25}=1-1+\dfrac{11}{25}=\dfrac{11}{25}\)b)\(=0,25-\dfrac{9}{4}:\dfrac{1}{4}+\dfrac{3}{2}.1=0,25-9+\dfrac{3}{2}=-7,25\)c)\(=\dfrac{25}{9}+\dfrac{9}{4}-\dfrac{5}{6}=\dfrac{151}{36}\)
phân thức xác định khi\(x^2+x-2\ne0\)\(x^2+2x-x-2\ne0\)\(x\left(x+2\right)-\left(x+2\right)\ne0\)\(\left(x-1\right)\left(x+2\right)\ne0\)\(x-1\ne0vàx+2\ne0\)\(x\ne1\) và \(x\ne-2\)
a. 124 + (118 – x) = 217 118 - x = 93 - x = - 25 x = 25
b. 7x – 8 = 713 7x =721 x =103
c. x- 36:18 = 12 x- 2 =12 x =14
d. (x- 36):18 = 12 x-36 = 216 x = 252
e. (x-47) -115 = 0 x-47 = 115 x = 162
f. 315 + (146 – x) = 401 146-x =86 -x = -60 x = 60
g. (6x – 39 ) : 3 = 201 6x - 39 = 603 6x = 642 x = 107
h. 23 + 3x = 56 : 53 23 +3x = 125 3x = 102 x=34
7045+2165:5-468=7 045 + 433 - 468=7010(1268+427)x(5-769)=1695x(-764)= - 1 294 980
a)=\(3.5.5+3.5.2-13=3.5\left(5+2\right)-13=15.7-13=105-13=92\)b)\(=5^3.2-25+2^3.5=5.25-5.5+8.5=5\left(25-5+8\right)=5.28=140\)c)\(6^2:9+50.2-3^3.3=36:9+100-3^4\)=\(4+100-81\)=23
gọi số cần tìm là a(a+1001)x3=99 999a+1001=99 999 : 3a+ 1001=33 333a=33 333-1 001a=32332
S=1+(2-3)+(-4+5)+(6-7)+(-8+9)+...+(-2020+2021)S=1-1+1-1+1+...+1S=1+0+0+...+0S=1