HOC24
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Bài học
\(=x^5y^4-x^3y^7-x^7y^3+x^3y^7^{ }\)=x5y4-x7y3
bất thường
267
bài 3 d) sin2a+cos2a=1\(\left(\dfrac{AC}{BC}\right)^2+\left(\dfrac{AB}{BC}\right)^2=\dfrac{AC^2}{BC^2}+\dfrac{AB^2}{BC^2}=\dfrac{BC^2}{BC^2}=1\)b)cot a =\(\dfrac{cosa}{sina}\)\(\dfrac{cosa}{sina}\)=\(\dfrac{AB}{\dfrac{BC}{\dfrac{AC}{BC}}}=\dfrac{AB}{AC}=cota\)
1, do you live,live2,are he doing , watering3,does she do , is4, are5, is playing, is playing 6, are watching7, go,have,am,visit8, Does your father go9,does your sister go10,do they get up11,do they do12, have13,is14,likes15, is calling16,am listening
1, I wish I knew more people2, I wish I had a key3,I wish Ann was here4, I wsh it wan't cold5, wish I didn't live in a big city6, I wish I couldn't go to the party7, I wish I hadn't to work tomorrow8, I wish I got good marks9, I wish i was lying on the beatiful sunny beach
1 met2,have known3, wil4, buy5,had gone6,travels
=\(\dfrac{2\sqrt{5}\left(\sqrt{5}+\sqrt{2}\right)}{\left(\sqrt{5}+\sqrt{2}\right)}-\dfrac{8\left(\sqrt{5}+1\right)}{\left(\sqrt{5}-1\right)\left(\sqrt{5}+1\right)}\)\(=2\sqrt{5}-\dfrac{8\left(\sqrt{5}+1\right)}{4}\)\(=2\sqrt{5}-2\left(\sqrt{5}+1\right)\)\(=2\sqrt{5}-2\sqrt{5}-2\)=-2
\(a.\sqrt{x-1}+\sqrt{4x-4}-\sqrt{25x-25}+2=0\)( x lớn hơn hoặc =1)\(\sqrt{x-1}+\sqrt{4\left(x-1\right)}-\sqrt{25\left(x-1\right)}\)+2=0\(\sqrt{x-1}\left(1+\sqrt{4}-\sqrt{25}\right)=-2\)\(\sqrt{x-1}\left(1+2-5\right)=-2\)\(\sqrt{x-1}.\left(-2\right)=-2\)\(\sqrt{x-1}=-2.2\)\(\sqrt{x-1}-4\)(ko thỏa mãn)b)\(\dfrac{1}{2}\sqrt{x-1}-\dfrac{3}{2}\sqrt{9x-9}+24\sqrt{\dfrac{x-1}{64}}=-17\)\(\dfrac{1}{2}\sqrt{x-1}-\dfrac{3}{2}\sqrt{9\left(x-1\right)}+24\dfrac{\sqrt{x-1}}{8}=-17\)\(\dfrac{1}{2}\sqrt{x-1}-\dfrac{3}{2}.3\sqrt{x-1}+3\sqrt{x-1}=-17\)\(\dfrac{1}{2}\sqrt{x-1}-\dfrac{9}{2}\sqrt{x-1}+3\sqrt{x-1}=-17\)\(\left(\dfrac{1}{2}-\dfrac{9}{2}+3\right)\sqrt{x-1}=-17\)\(7\sqrt{x-1}=-17\)\(\sqrt{x-1}=-\dfrac{17}{7}\)(ko thỏa mãn căn bậc 2 ko có số âm)
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