HOC24
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a)\(5^6:5^4+3^2-2021^0=5^2+3^2-1=25+9-1=33\)b)\(100-\left[60-\left(9-2^3\right).34\right].2=100-\left[60-\left(9-8\right).34\right].2\)\(=100-\left(60-1.34\right).2=100-\left(60-34\right).2=100-26.2=100-52=48\)
BB
đâu có làm tắt đâukiến thức 2 góc trong cùng phía bù nhau thì chỉ cần 1 dòng là đc mà
a)\(\sqrt{\left(x-4\right)^2}=2x+7\)TH1 \(x\ge4\)=>x-4 = 2x+7-x=11x=-11 ( không thỏa mãn )TH2x<4=> -x+4=2x+7=> -3x=3=>x=-1b)\(5-\sqrt{\left(x-1\right)^2}=0\)\(-\left|x-1\right|=-5\)\(\left|x-1\right|=5\)TH1 x\(\ge1\)x-1=5x=6TH2 x<1-x+1=5-x=4x=-4(ko thỏa mãn)
2 . 53 . 27 + 6 . 9 . 87 - 3 . 18 . 40 = 2. 53 . 9 . 3 + 2. 3 .9 .87 - 3 .2 .9 .40= 54.53+54.87-54.40=54(53+87-40)=54. 100=5400
12 . 25 + 29 . 25 + 59 . 25 = 25 . ( 12+29+59)=25 . 90=2250
43 . 37 + 93 . 43 + 57 . 61 + 69 . 57 = 43.(37+93)+57(61+69)=43.130+57.130=130.(43+57)=130.100=13 000
12 . 53 + 53 . 172 - 53 =53(12+172-1)=53.184=9752
35 . 54 + 35 . 58 + 65 . 75 + 65 . 45 =35(54+58)+65(75+45)=35.112+65.120=3920+7800=11720
39 . 8 + 70 . 3 + 31 . 8 =8(39+31)+70.3=8.70+70.3=70.(8+3)=70.11=770
bài 1a)=(x+y-x+y)(x+y+x-y)=2x.2y=4xyb)B=(x+y-x+y)2=4y2c)=(x+y-x+y)[(x+y)2+(x+y)(x-y)+(x-y)2]-2y3=2y(\(x^2+2xy+y^2+x^2-y^2+x^2-2xy+y^2\))-2y3=\(2y\left(3x^2+y^2\right)-2y^3=6x^2y+2y^3-2y^3=6x^2y\)
bài 5góc BAb=1800-1200=600mà B1=góc BAb=600(so le trong)bài 7có góc BDC=1800- góc BDb=1800-1500=300=>góc BDC= góc aBD=>a//b=>A1=góc ACD=700=>A2=1800-ACD=1800-700=1100
A4=1800-A1=1800-600=1200A1=B3(so le trong)mà B3=B1(đối đỉnh)=>A1=B1=600=>A1=B3=600
A mấy = 60 kia
\(A=\dfrac{x^3\left(x+1\right)+\left(x+1\right)}{x^2\left(x+1\right)-\left(x+1\right)}=\dfrac{\left(x^3+1\right)\left(x+1\right)}{\left(x^2-1\right)\left(x+1\right)}\)\(=\dfrac{x^3+1}{x^2-1}=\dfrac{\left(x+1\right)\left(x^2-x+1\right)}{\left(x+1\right)\left(x-1\right)}=\dfrac{x^2-x+1}{x-1}\)