4³.4^x=4¹⁶
4^3+x=4¹⁶
3+x=16
x=13

\(3\dfrac{1}{3}+\dfrac{5}{6}=\dfrac{10}{3}+\dfrac{5}{6}=\dfrac{20}{6}+\dfrac{5}{6}=\dfrac{25}{6}\)
\(4\dfrac{5}{7}-2\dfrac{11}{21}=\dfrac{33}{7}-\dfrac{53}{21}=\dfrac{99}{21}-\dfrac{53}{21}=\dfrac{46}{21}\)
\(3\dfrac{1}{4}x\dfrac{2}{5}=\dfrac{13}{3}x\dfrac{2}{5}=\dfrac{26}{15}\)
\(4\dfrac{7}{8}:\dfrac{1}{4}=\dfrac{39}{8}.4=\dfrac{39}{2}\)

\(\dfrac{2020}{2019}-\dfrac{2019}{2018}+\dfrac{1}{2019}x2018\)
\(=\dfrac{2020}{2019}-\dfrac{2019}{2018}+\dfrac{2018}{2019}=2-\dfrac{2019}{2018}=\dfrac{2017}{2018}\)

b)
73hm²
2,000075m²
c

sắp sang đông r

thứ 6 tuần sau thu ạ

đầu bài cho rất chi tiết rồi
\(B=\left[\left(x-y\right)-z\right]^3=\left(x-y-z\right)^3\)

0,25m²
180 giây

\(C=6\left(c-d\right)\left(c+d\right)\left(c+d\right)+12\left(c-d\right)\left(c-d\right)\left(c+d\right)+c^3+3c^2d+3cd^2+d^3+8\left(c^3-3c^2d+3cd^2-d^3\right)\)
​​​\(C=6\left(c^2-d^2\right)\left(c+d\right)+12\left(c-d\right)\left(c^2-d^2\right)+c^3+3c^2d+3cd^2+d^3+8\left(c^3-3c^2d+3cd^2-d^3\right)\)​\(C=6\left(c^3+c^2d-cd^2-d^3\right)+12\left(c^3-c^2d-cd^2-d^2\right)+c^3+3c^2d+3cd^2+d^3+8\left(c^3-3c^2d+3cd^2-d^3\right)\)
\(C=27c^3-27c^2d-39cd^2-25d^3\)
 

\(B=\left(x-y-z\right)^3\)