\(\sqrt{x+1}+1=4x^2+\sqrt{3x}\left(x\ge0\right)\\ \Leftrightarrow\sqrt{x+1}+\sqrt{3x}=4x^2-1\\ \Leftrightarrow\dfrac{1-2x}{\sqrt{x+1}-\sqrt{3x}}=\left(2x-1\right)\left(2x+1\right)\\ \Leftrightarrow\left(1-2x\right)\left(\dfrac{1}{\sqrt{x+1}-\sqrt{3x}}+2x+1\right)=0\\ \Leftrightarrow x=\dfrac{1}{2}\)

Vì biểu thức trong ngoặc còn lại lớn hơn 0 với mọi \(x\ge0\) bằng cách khảo sát hàm số ta sẽ nhận ra điều này.

à thêm \(x-1\ne0\Leftrightarrow x\ne1\)

\(\sqrt{\dfrac{1}{x-1}}\)

\(ĐKXĐ:\dfrac{1}{x-1}>0\Leftrightarrow x-1>0\left(1>0\right)\Leftrightarrow x>1\)

Làm hộ đc bao nhiu thì đc nha

7. The policeman asked us not to touch anything in the room.

8. Mary asked John if he could carry her suitcase.

9. Mr Atkins said to David that he mustn't leave the door unlocked.

10.I asked my neighbors if they minded turning their music down.

\(x^2-6=\left(x-\sqrt{6}\right)\left(x+\sqrt{6}\right)\)

\(x^{16}-1\\ =\left(x^8-1\right)\left(x^8+1\right)\\ =\left(x^4-1\right)\left(x^4+1\right)\left(x^8+1\right)\\ =\left(x^2-1\right)\left(x^2+1\right)\left(x^4+1\right)\left(x^8+1\right)\\ =\left(x-1\right)\left(x+1\right)\left(x^2+1\right)\left(x^4+1\right)\left(x^8+1\right)\)

Tick hộ nha 😘

nhầm sorry

\(\left(\dfrac{x-3\sqrt{x}}{x-9}-1\right):\left(\dfrac{9-x}{x+\sqrt{x}-6}+\dfrac{\sqrt{x}-3}{\sqrt{x}-2}-\dfrac{\sqrt{x}-2}{\sqrt{x}+3}\right)\left(x\ge0;x\ne3;x\ne-3;x\ne9;x\ne4\right)\)

\(=\left(\dfrac{\sqrt{x}\left(\sqrt{x}-3\right)}{\left(\sqrt{x}-3\right)\left(\sqrt{x}+3\right)}-1\right):\left(\dfrac{9-x}{\left(\sqrt{x}+3\right)\left(\sqrt{x}-2\right)}+\dfrac{\sqrt{x}-3}{\sqrt{x}-2}-\dfrac{\sqrt{x}-2}{\sqrt{x}+3}\right)\\ =\dfrac{\sqrt{x}-\sqrt{x}-3}{\sqrt{x}+3}:\dfrac{9-x+\left(\sqrt{x}-3\right)\left(\sqrt{x}+3\right)-\left(\sqrt{x}-2\right)\left(\sqrt{x}-2\right)}{\left(\sqrt{x}+3\right)\left(\sqrt{x}-2\right)}\\ =\dfrac{-3}{\sqrt{x}+3}:\dfrac{9-x+x-9-x+4\sqrt{x}-4}{\left(\sqrt{x}+3\right)\left(\sqrt{x}-2\right)}\\ =\dfrac{-3}{\sqrt{x}+3}\cdot\dfrac{\left(\sqrt{x}+3\right)\left(\sqrt{x}-2\right)}{-\left(\sqrt{x}-2\right)^2}\\ =\dfrac{3}{\sqrt{x}-2}\)

Tick hộ nha 😘

Because I didn't have a map, I got lost.