Câu trả lời:
| GT | \(AB=6\left(cm\right);AC=8\left(cm\right)\\
\Delta ABC\perp A\) Đường cao `AH` |
| KL | \(\Delta ABC\sim\Delta HBA\) |
Vì \(\left\{{}\begin{matrix}\widehat{BAC}=\widehat{BHA}=90^0\\\widehat{ABC}\text{ chung}\end{matrix}\right.\to\Delta ABC\sim\Delta HBA\left(g.g\right)\)