\(\Rightarrow2^x+16=64\\ \Rightarrow2^x=48\Rightarrow x\in\varnothing\)

\(\Rightarrow\dfrac{\left(n+2018+n+1\right)\cdot2018}{2}=2021\cdot2019\\ \Rightarrow\left(2n+2019\right)\cdot1009=2021\cdot2019\\ \Rightarrow2018n+2019\cdot1009=2021\cdot2019\\ \Rightarrow2018n=2019\left(2021-1009\right)=2019\cdot1012\\ \Rightarrow n=\dfrac{2019\cdot1012}{2018}=\dfrac{2031114}{1009}\)

\(\Rightarrow\dfrac{x}{5}=\dfrac{y}{2}=\dfrac{2x-y}{10-2}=\dfrac{16}{8}=2\\ \Rightarrow\left\{{}\begin{matrix}x=10\\y=4\end{matrix}\right.\)