1 + 2 = 3 nhé

\(\frac{a^2-2ab}{a^2b}.P=\frac{a^2b-4b^3}{3ab^2}\)

\(P=\frac{a^2b-4b^3}{3ab^2}:\frac{a^2-2ab}{a^2b}\)

\(P=\frac{a^2b-4b^3}{3ab^2}.\frac{a^2b}{a^2-2ab}\)

\(P=\frac{b\left(a^2-4b^2\right)}{3ab^2}.\frac{a^2b}{a\left(a-2b\right)}\)

\(P=\frac{b\left(a-2b\right)\left(a+2b\right)}{3ab^2}.\frac{a^2b}{a\left(a-2b\right)}\)

\(P=\frac{b\left(a+2b\right)}{3b}.\frac{a}{a}\)

\(P=\frac{a+2b}{3}\)

C = ! x-3 ! - !x-2!

C = x - 3 - x + 2

C = -1

Dấu ! là trị tuyệt đối nha bạn