\(4,-3a\left(x-3\right)-a^2\left(3-x\right)\\ =-3a\left(x-3\right)+a^2\left(x-3\right)\\ =\left(x-3\right)\left(a^2-3a\right)\\ =a\left(x-3\right)\left(a-3\right)\\ 5,2a^2b\left(x+y\right)-4a^3b\left(-x-y\right)\\ ==2a^2b\left(x+y\right)+4a^3b\left(x+y\right)\\ =\left(x+y\right)\left(2a^2b+4a^3b\right)\\ =\left(x+y\right)2a^2b\left(1+a\right)\\ 6,7a\left(x-2y\right)-14a^2\left(2y-x\right)\\ =7a\left(x-2y\right)+14a^2\left(x-2y\right)\\ =\left(x-2y\right)\left(7a+14a^2\right)\\ =\left(x-2y\right)7a\left(1+2a\right)\)

ấn đc mà:v

\(A=\sqrt{3+\sqrt{5-\sqrt{13+\sqrt{48}}}}\\ =\sqrt{3+\sqrt{5-\sqrt{\left(1+2\sqrt{3}\right)^2}}}\\ =\sqrt{3+\sqrt{5-1+2\sqrt{3}}}\\ =\sqrt{3+\sqrt{\left(\sqrt{3}-1\right)^2}}\\ =\sqrt{3+\sqrt{3}-1}\\ =\sqrt{2+\sqrt{3}}\)

đề bài bạn âyyyyy

thiếu đề bài bạn âyyy =))

ko thấy gj nha=)))