\(x:\dfrac{1}{4}=8\\ x=8\times\dfrac{1}{4}\\ x=2\)

\(a,A=\dfrac{2}{3}x^3y.\dfrac{3}{4}xy^2z^2=\dfrac{1}{2}x^4y^3z^2\)

b, Bậc:9

c, Hệ số: `1/2`

Biến: x⁴y³z²

d, Thay x=-1, y=-2, z=-3 vào A ta có:
\(A=\dfrac{1}{2}x^4y^3z^2=\dfrac{1}{2}\left(-1\right)^4.\left(-2\right)^3.\left(-3\right)^2=\dfrac{1}{2}.\left(-8\right).9=-36\)

a,<

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c,=

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12m²

\(x-\dfrac{3}{4}=\dfrac{1}{2}\\ x=\dfrac{1}{2}+\dfrac{3}{4}\\ x=\dfrac{2}{4}+\dfrac{3}{4}\\ x=\dfrac{5}{4}\)

40%

D

đây là điều bắt buộc, nói như bạn oan lắm

ghi tham khảo vào, chắc chắn đây ko phải bn lm

\(\dfrac{5}{12}-\dfrac{7}{32}:\dfrac{21}{16}=\dfrac{5}{12}-\dfrac{7}{32}\times\dfrac{16}{21}=\dfrac{5}{12}-\dfrac{1}{6}=\dfrac{5}{12}-\dfrac{2}{12}=\dfrac{3}{12}=\dfrac{1}{4}\)