Tìm x để \(\frac{3}{2+\sqrt{x}}\) = \(\frac{6}{5}\)

Tìm x để -9. \(\frac{1}{x-4}\)=-1

A = \(10-\left(\sqrt{32}-\sqrt{8}-\sqrt{27}\right)\left(\sqrt{8}-\sqrt{32}-\sqrt{27}\right)\)

Rút gọn B

B = \(\frac{1}{\sqrt{x}-2}+\frac{1}{\sqrt{x}+2}+\frac{2\sqrt{x}-1}{4-x}\)