Khi mà em đưa lên hết nó đều mạnh thẳng nha.

147.C

\(C_nH_{2n+2}\)

\(n_{H_2O}=\dfrac{7.2}{18}=0.4\left(mol\right)\)

\(\Rightarrow0.1\cdot\left(2n+2\right)=0.4\cdot2\)

\(\Rightarrow n=3\)

\(CT:C_3H_8\) propan

\(4P+5O_2\underrightarrow{^{^{t^0}}}2P_2O_5\)

\(Fe_2O_3+3H_2\underrightarrow{^{^{t^0}}}2Fe+3H_2O\)

\(CuO+H_2\underrightarrow{^{^{t^0}}}Cu+H_2O\)

\(2Mg+O_2\underrightarrow{^{^{t^0}}}2MgO\)

\(n_{Zn}=\dfrac{13}{65}=0.2\left(mol\right)\)

\(Zn+2HCl\rightarrow ZnCl_2+H_2\)

\(0.2....................0.2..........0.2\)

\(m_{ZnCl_2}=0.2\cdot136=27.2\left(g\right)\)

\(V_{H_2}=0.2\cdot22.4=4.48\left(l\right)\)

\(n_P=\dfrac{6.2}{31}=0.2\left(mol\right)\)

\(n_{O_2}=\dfrac{8.96}{22.4}=0.4\left(mol\right)\)

\(4P+5O_2\underrightarrow{^{^{t^0}}}2P_2O_5\)

\(4........5\)

\(0.2.........0.4\)

Lập tỉ lệ : \(\dfrac{0.2}{4}< \dfrac{0.4}{5}\Rightarrow O_2dư\)

\(n_{P_2O_5}=0.2\cdot\dfrac{2}{4}=0.1\left(mol\right)\)

\(m_{P_2O_5}=0.1\cdot142=14.2\left(g\right)\)

\(m_{P_2O_5\left(tt\right)}=14.2\cdot80\%=11.36\left(g\right)\)

\(Fe+2HCl\rightarrow FeCl_2+H_2\)

\(0.1...........0.2\)

\(Fe+CuCl_2\rightarrow FeCl_2+Cu\)

Vì khối lượng thanh sắt không đổi nên m_tăng = m_giảm

\(0.1\cdot56=a\cdot\left(64-56\right)\)

\(\Rightarrow a=0.7\)