\(2Fe+6H_2SO_{4\left(đ\right)}\underrightarrow{^{^{t^0}}}Fe_2\left(SO_4\right)_3+3SO_2+6H_2O\)

1. He was not allowed to come in because he was late.

=> Because of his late arrival, he was not allowed to come.

Đổi thành 1.302083 (tấn) nhé !

\(n_P=\dfrac{150}{31}\left(kmol\right)\)

\(Ca_3\left(PO_4\right)_2+3SiO_2+5C\underrightarrow{^{^{t^0}}}3CaSiO_3+2P+5CO\)

\(\dfrac{75}{31}.....................................\dfrac{75}{31}\)

\(m_{Ca_3\left(PO_4\right)_2}=\dfrac{75}{31}\cdot310=750\left(kg\right)\)

\(\Rightarrow m_{Ca_3\left(PO_4\right)_2\left(tt\right)}=\dfrac{750}{96\%}=781.25\left(kg\right)\)

\(m_{quặng}=\dfrac{781.25}{60\%}=1302.083\left(kg\right)\)

Nguyên tử Calcium có 20p và 20n.

\(Na+H_2O\rightarrow NaOH+\dfrac{1}{2}H_2\)

\(CuO+H_2O\rightarrow X\)

\(SO_3+H_2O\rightarrow H_2SO_4\)

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