\(\sqrt[3]{x+2}+\sqrt[3]{x-2}=\sqrt[3]{5x}\)

Sentence Tranformation:

1.No snowing storm is as heavy as this one.-> This is ................................................................................

2.Hanh cooks the best in her family.-> Nobody................................................................................

3.All the students have gained more progress than Tuan.->Tuan................................................................................

4.Janpanese is mre difficult than Spanish.-> Spanish................................................................................

5.Nobody can speak Chinese as fluently as Jack.-> Jack................................................................................

6.Mike is three years older than you.-> You................................................................................

7.I have never a more charming girl than Julie.

Julie is................................................................................

8.Tom is not as generous as Henry is.-> Henry is................................................................................

9.Joe has three brothers more than me.-> I have three brothers................................................................................

10.My sister has much more money than toy do.-> You have................................................................................

11.Terry plays badminton more regularly than Dave->Dave................................................................................

12.Nobody is more anxious to help you than your mother.

Your mother................................................................................

13.Janet is the best tennis player the club.-> No one ia the club................................................................................

14.All the student could write eassys better than Tuan.-> Tuan................................................................................

15.The amount of rice exported to the Philippine in 2008 was as large as that to Indonesia

Rewrite the sentences:

1.I didn't spend as much noney as you.-> You ............................................................................

2.Yesterday the temperature was only 9 degrees.But,today it is up to 19 degrees

It's ............................................................................

3.They didn't come as early as expected.

They came ............................................................................

4.Trains are faster than buses.-> Buses ............................................................................

5.Lilly is more beautiful than Sue.-> Sue ............................................................................

6.Pat listens to teachers less attentive than others.

Pat doesn't ............................................................................

7.Physics is not as easy as history.

History ............................................................................

8.Hung learns better than Mai.-> Mai ............................................................................

9.Nobody in our class is as fat as Long.-> Long ............................................................................

10.Nothing is more precious than independenc and freedom

cho tam giác ABC có AB=6,AC=4.5,BC=7.5.C/m:

a.tam giác ABC vuông tại A

b.tính AH,góc B,góc C

c.Tìm tập hợp điểm M sao cho \(S_{ABC}=S_{BMC}\)

cho tam giác ABC,BC=8,góc ABC = 40, góc ACB = 30, AH là đường cao.Tính AH,AC?

\(x=\sqrt[3]{\sqrt{5}+2}+\sqrt[3]{\sqrt{5}-2}\)

\(x=\sqrt[3]{5+2\sqrt{13}}+\sqrt[3]{5-2\sqrt{13}}\)

1.Tính các giá trị biểu thức:

a.\(x=\sqrt[3]{5+2\sqrt{3}}+\sqrt[3]{5-2\sqrt{3}}\)

b.\(x=\sqrt[3]{\sqrt{5}+2}-\sqrt[3]{\sqrt{5}-2}\)

c.\(x=\sqrt[3]{182+\sqrt{33125}}+\sqrt[3]{182-\sqrt{33125}}\)

d.\(x=\sqrt[3]{20+14\sqrt{2}}+\sqrt[3]{20-14\sqrt{2}}\)

1.\(x=\sqrt[3]{14+2\sqrt{47}}+\sqrt[3]{14-2\sqrt{47}}\)

Tính \(f\left(x\right)=x^3-6x\)

cho hình vuông ABCD , ,AM BC ở E , dAM ở A , d CD ở N , O là trung điểm EN. chứng minh :
a) B,D,O thẳng hàng
b) \(\frac{1}{AB^2}=\frac{1}{AM^2}+\frac{1}{AE^2}\)

c)OA⊥NE

d)\(\frac{1}{AD^2}\)≥\(\frac{2}{AM.AE}\)