Trình bày thuật toán bài toán tính tổng S=1+2+3+.......+100

100 - 9  : ( x + 1)= 19
9 : ( x + 1 ) = 100 - 19
9 : ( x + 1 ) = 81
x + 1 = 9 : 81
x + 1 = \(\frac{1}{9}\)
 

Ta có: \(3x-xy-y+2=0\)

\(\Rightarrow x.\left(3-y-y\right)+2=0\)

\(\Rightarrow3x+2=0\)\(\Rightarrow3x=0-2=-2\)

\(\Rightarrow x=-2:3=\frac{-2}{3}\)

\(\Rightarrow y=0\)

27¹³=3.( (9.3)¹³) = (9 x 9)¹³ = 9¹⁴

Vậy 9¹⁴ = 9²⁰ nên 9^20 > 27^13

dug ròi đó

h minh di

\(S=2+\frac{1}{2+\frac{1}{2+\frac{1}{2}}}=2+\frac{1}{2+\frac{1}{\frac{5}{2}}}=2+\frac{1}{2+\frac{2}{5}}=2+\frac{1}{\frac{12}{5}}=2+\frac{5}{12}=\frac{29}{12}\)

Ta có: \(S=2+\frac{1}{2+\frac{1}{2+\frac{1}{2}}}=2+\frac{1}{2+\frac{1}{\frac{5}{2}}}=2+\frac{1}{2+\frac{2}{5}}\)

                                                       \(=2+\frac{1}{\frac{12}{5}}=2+\frac{5}{12}=\frac{29}{12}\)

nha m.n

2^x = 8

2^x =  2^3

x = 3