a) |x(x-1)|=x^2-x

b) |x^2+2x+3| + |x-1| = 6

Giải phương trình

x^2 - x ≥ 0

a) |x(x-1)|=x^2-x

b) |x^2+2x+3| + |x-1| = 6

a) |x(x-1)|=x^2-x

b) |x^2+2x+3| + |x-1| = 6

a) |x(x-1)|=x^2-x

b) |x^2+2x+3| + |x-1| = 6

a) |x(x-1)|=x^2-x

b) |x^2+2x+3| + |x-1| = 6

a) |x(x-1)|=x^2-x

b) |x^2+2x+3| + |x-1| = 6

a) |x(x-1)|=x^2-x

b) |x^2+2x+3| + |x-1| = 6

a(b+c-a)^2 + b(c+a-b)^2 + c(a+b-c)^2 + (a+b-c)(b+c-a)(c+a-b)

tai nguoi do di lui