\(\frac{3}{2}x\)---\(\frac{2}{5}\)= \(\frac{1}{3}\)x\(\frac{1}{3}x\) --- \(\frac{1}{4}\)
2/ 2x --\(\frac{1}{4}\)= \(\frac{5}{6}\)--- \(\frac{1}{2}x\)
3/ \(-\frac{5}{6}\)+ 3x = \(\frac{2}{3}\)--- \(\frac{1}{2}x\)
4/ \(\frac{5}{3}\)[ 3x --- 3 ] + \(\frac{1}{2}\)= \(\frac{1}{2}\)[ 2x ---- 1 ]