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Người theo dõi (30)

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Thiên Hàn

Câu trả lời:

Bài 1:

a) \(25\left(x+2y\right)^2-16\left(2x-y\right)^2\)

\(=\left[5\left(x+2y\right)\right]^2-\left[4\left(2x-y\right)\right]^2\)

\(=\left[5\left(x+2y\right)-4\left(2x-y\right)\right]\left[5\left(x+2y\right)+4\left(2x-y\right)\right]\)

\(=\left(5x+10y-8x+4y\right)\left(5x+10y+8x-4y\right)\)

\(=\left(14y-3x\right)\left(13x+6y\right)\)

b) \(0,25\left(x-2y\right)^2-4\left(x+y\right)^2\)

\(=\left[\dfrac{1}{2}\left(x-2y\right)\right]^2-\left[2\left(x+y\right)\right]^2\)

\(=\left[\dfrac{1}{2}\left(x-2y\right)-2\left(x+y\right)\right]\left[\dfrac{1}{2}\left(x-2y\right)+2\left(x+y\right)\right]\)

\(=\left(\dfrac{1}{2}x-y-2x-2y\right)\left(\dfrac{1}{2}x-y+2x+2y\right)\)

\(=\left(-\dfrac{3}{2}x-3y\right)\left(\dfrac{5}{2}x+y\right)\)

\(=-3\left(\dfrac{1}{2}x+y\right)\left(\dfrac{5}{2}x+y\right)\)

c) \(\dfrac{4}{9}\left(x-3y\right)^2-0,04\left(x+y\right)^2\)

\(=\left[\dfrac{2}{3}\left(x-3y\right)\right]^2-\left[\dfrac{1}{5}\left(x+y\right)\right]^2\)

\(=\left[\dfrac{2}{3}\left(x-3y\right)-\dfrac{1}{5}\left(x+y\right)\right]\left[\dfrac{2}{3}\left(x-3y\right)+\dfrac{1}{5}\left(x+y\right)\right]\)

\(=\left(\dfrac{2}{3}x-2y-\dfrac{1}{5}x-\dfrac{1}{5}y\right)\left(\dfrac{2}{3}x-2y+\dfrac{1}{5}x+\dfrac{1}{5}y\right)\)

\(=\left(\dfrac{7}{15}x-\dfrac{11}{5}y\right)\left(\dfrac{13}{15}x-\dfrac{9}{5}y\right)\)

\(=\dfrac{1}{5}\left(\dfrac{7}{3}x-11y\right).\dfrac{1}{5}\left(\dfrac{13}{3}x-9y\right)\)

\(=\dfrac{1}{25}\left(\dfrac{7}{3}x-11y\right)\left(\dfrac{13}{3}x-9y\right)\)

d) \(-25x^2+30x-9\)

\(=-\left(25x^2-30x+9\right)\)

\(=-\left[\left(5x\right)^2-2.5x.3+3^2\right]\)

\(=-\left(5x-3\right)^2\)

Bài 2:

a) \(x^3y^2-x^2y^3-2x+2y\)

\(=x^2y^2\left(x-y\right)-2\left(x-y\right)\)

\(=\left(x-y\right)\left(x^2y^2-2\right)\)

Thay x = -1 và y = -2 vào ta được

\(=\left[-1-\left(-2\right)\right]\left[\left(-1\right)^2\left(-2\right)^2-2\right]\)

\(=1\left(4-2\right)\)

\(=2\)

b) \(5x^2-3x+3y-5y^2\)

\(=5\left(x^2-y^2\right)-3\left(x-y\right)\)

\(=5\left(x-y\right)\left(x+y\right)-3\left(x-y\right)\)

Thay x = 3 và y = 1 vào ta được

\(=5\left(3-1\right)\left(3+1\right)-3\left(3-1\right)\)

\(=5.2.4-3.2\)

\(=34\)