khi lên cao 100 m nhiệt độ giảm 0,6 độ

 khi lên cao 1000m thù nhiệt độ không khí là:

              240-0,6x(1000:100)=234(độ )

2A = 2( 5/2.4 + 5/4.6 +...+ 5/48.50 )

2A = 5( 2/2.4 + 2/4.6 +...+ 2/48.50 )

2A = 5( 1/2-1/4 + 1/4-1/6 +...+ 1/48-1/50 )

2A = 5( 1/2-1/50 )

2A = 5.24/50 → A= 5.24/25 = 24/5

a.X=14:2     B,X=877-56

  X=7              X=821

40 ga 

10 lon

a) x = 14 x 2                                                             b) x = 877 - 56

   x = 28                                                                       x =821

\(\frac{2a-b}{a+b}=\frac{b-c+a}{2a-b}=\frac{2}{3}\)

\(\Rightarrow\frac{2a-b}{a+b}=\frac{b-c+a}{2a-b}=\frac{\left(2a-b\right)+\left(b-c+a\right)}{\left(a+b\right)+\left(2a-b\right)}=\frac{3a-c}{3a}=\frac{2}{3}\)

\(\Rightarrow2\times3a=3\times\left(3a-c\right)\)

\(\Rightarrow6a=9a-3c\)

\(\Rightarrow6a-9a=-3c\)

\(\Rightarrow-3a=-3c\)

\(\Rightarrow\frac{-3a}{-3}=\frac{-3c}{-3}\)

\(\Rightarrow a=c\)

\(\Rightarrow\frac{\left(5b+4a\right)^5}{\left(5b+4c\right)^2\left(a+3c\right)^3}=\frac{\left(5b+4a\right)^5}{\left(5b+4a\right)^2\left(a+3a\right)^3}=\frac{\left(5b+4a\right)^3}{\left(4a\right)^3}\)

\(\frac{2a-b}{a+b}=\frac{2}{3}\)

\(\Rightarrow3\times\left(2a-b\right)=2\left(a+b\right)\)

\(\Rightarrow6a-3b=2a+2b\)

\(\Rightarrow6a-2a=3b+2b\)

\(\Rightarrow4a=5b\)

\(\Rightarrow b=\frac{4a}{5}\)

\(\Rightarrow\frac{\left(5b+4a\right)^3}{\left(4a\right)^3}=\left(\frac{5\times\frac{4a}{5}+4a}{4a}\right)^3=\left(\frac{4a+4a}{4a}\right)^3\)

\(\Rightarrow\left(\frac{8a}{4a}\right)^3=2^3=8\)

 đề toán cho học sinh mẫu giáo
 

là con chó sói

úm ba la xì bùa