Bài 1) tự làm
Bài 2
A) x-\(\dfrac{1}{2}\)= \(\dfrac{-1}{6}\)
x= \(\dfrac{-1}{6}\)+\(\dfrac{1}{2}\)
x= \(\dfrac{-1}{6}\)+ \(\dfrac{3}{6}\)
x= \(\dfrac{2}{6}\)=\(\dfrac{1}{3}\)
B)\(\dfrac{1}{2}\)+\(\dfrac{5}{6}\):x= \(\dfrac{1}{3}\)
(\(\dfrac{3}{6}\)+\(\dfrac{5}{6}\)):x=\(\dfrac{1}{3}\)
\(\dfrac{8}{6}\):x=\(\dfrac{1}{3}\)
x=\(\dfrac{1}{3}\).\(\dfrac{8}{6}\)
x= \(\dfrac{8}{18}\)=\(\dfrac{4}{9}\)
C) tự làm
D)|x+\(\dfrac{3}{8}\)|-1=\(\dfrac{1}{2}\)
|x+\(\dfrac{3}{8}\)| = \(\dfrac{1}{2}\)+1
|x+\(\dfrac{3}{8}\)| =\(\dfrac{3}{2}\)
x +\(\dfrac{3}{8}\) = \(\dfrac{3}{2}\) hoặc x +\(\dfrac{3}{8}\) =\(\dfrac{-3}{2}\)
x = \(\dfrac{3}{2}\)-\(\dfrac{3}{8}\) x = \(\dfrac{-3}{2}\)-\(\dfrac{3}{8}\)
x = \(\dfrac{12}{8}\)-\(\dfrac{3}{8}\) x = \(\dfrac{-12}{8}\)-\(\dfrac{3}{8}\)
x = \(\dfrac{9}{8}\) x = \(\dfrac{-15}{8}\)