Tìm

Min Q = \(\dfrac{x^2-3x+3}{\left(x-1\right)^2}\) ∀ \(x\ne1\)

Tìm

Max Q=\(\dfrac{5}{x^2-2x+5}\)

Gợi ý : A ≥ B > 0 = \(\dfrac{1}{A}\le\dfrac{1}{B}\)

Chứng minh

\(2x^2+2y^2-2xy-4x-4y+8\ge0\forall x;y\)

Tìm

Min Q=\(\dfrac{x^2-3x+3}{\left(x-1\right)^2}\forall x\ne1\)

Tìm

Max Q=\(\dfrac{5}{x^2-2x+5}\)

( Gợi ý: A≥B>0 ⇔ \(\dfrac{1}{A}\le\dfrac{1}{B}\)

Find the word which should not be in the sentence.

I'll give them my new address in case they will want to forward my post .