Câu trả lời:

có m > 1 \(\Rightarrow\)\(\sqrt{m}>\sqrt{1}\Rightarrow\sqrt{m}>1\Rightarrow\sqrt{m}.\sqrt{m}>\sqrt{m}\Rightarrow m>\sqrt{m}\)

b, có m<1 =>\(\sqrt{m}< 1\Rightarrow\sqrt{m}.\sqrt{m}< \sqrt{m}\Rightarrow m< \sqrt{m}\)