a:5 dư 3 vậy a cách 5 3 đơn vị

a=8

a³=8.8.8=2⁹=512 vậy a³:5 dư 2

Sao mà mày ngu wa z 2+9= mà bằng mấy

=11 chứ bây nhiêu

dễ

Ko

Giai

\(a=-90\\ b=-120\\ c=-12\\ d=288\\ e=26\)

\(x^4=4x+1\\ \Leftrightarrow x^4-4x=1\\ \Leftrightarrow x\left(x^3+4\right)=1\\ x\approx-0,3\)

\(\Rightarrow S=\left\{\varnothing\right\}\)

Giải

\(\frac{x+2}{x-2}+\frac{x-1}{x+2}=\frac{2\left(x^2+2\right)}{x^2-4}\\ĐKXĐ:x\ne2;-2\\ MTC:\left(x-2\right)\left(x+2\right)\\ \frac{\left(x+2\right)\left(x-2\right)}{\left(x-2\right)\left(x+2\right)}+\frac{\left(x-1\right)\left(x-2\right)}{\left(x+2\right)\left(x-2\right)}=\frac{2\left(x^2+2\right)}{\left(x-2\right)\left(x+2\right)}\\ \left(x+2\right)\left(x-2\right)+\left(x-1\right)\left(x-2\right)=2\left(x^2+2\right)\\ x^2-4+x^2-3x+2=2x^2+4\\ x^2-4+x^2-3x+2-2x^2=4\\-3x=6\\ x=-2 \)