HOC24
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Bài học
\(Đk:\)\(x\)\(\ne\)\(0\) và x\(\ne\)\(5\)
\(\Leftrightarrow\)\(\dfrac{x(x+5)-(x-5)}{x(x-5)}=\dfrac{5}{x(x-5)}\)
\(\Leftrightarrow\)\(\dfrac{x^2+5x-x+5}{x(x-5)}-\dfrac{5}{x(x-5)}=0\)
\(\Leftrightarrow\)\(\dfrac{x^2+4x}{x(x-5)}=0\)
\(\Rightarrow\)\(x^2+4x=0\)
\(\Leftrightarrow\)\(\left[\begin{array}{} x=0\\ x+4=0 \end{array} \right.\)
\(\Leftrightarrow\)\(\left[\begin{array}{} x=0(loại)\\ x=-4(thỏa mãn) \end{array} \right.\)
a)R
b)R
c)\(x\)\(\ne\)\(\pm\)\(1\)
d)\(x<1\)
\(A=\dfrac{3}{7}+(-\dfrac{5}{2})+(-\dfrac{3}{7})\)
\(=(\dfrac{3}{7}-\dfrac{3}{7})-\dfrac{5}{2} \)
\(=-\dfrac{5}{2}\)
\(B=\dfrac{4^2.2^3}{2^6}\)
\(B=\dfrac{4^2}{2^3}\)
\(B=\dfrac{16}{8}\)
\(B=2\)
1)
\(a)2^x=2^4\)
\(\Leftrightarrow\)\(x=4\)
\(b)\)\(x^{50}=x\)
\(\Leftrightarrow\)\(x=0\)
2)
\(a)x^3=-3^3 \)
\(\Leftrightarrow\)\(x=-3\)
\(b)(x-2)^2=4^2\)
\(\Leftrightarrow\)\(x-2=4\)
\(\Leftrightarrow\)\(x=6\)
Biểu thức này không phân tích được nhé.
Rườm quá e.Nhân giãn ra rồi tính sẽ nhanh hơn
\(= \)\(5x^2-4x^2+8x-4-5\)
\(=\)\(x^2+8x-9\)
\(=x^2+9x-x-9\)
\(=(x-1)(x+9)\)
\(x-\dfrac{9}{2}=-\dfrac{5}{2}\)
\(\Leftrightarrow\)\(x=-\dfrac{5}{2}+\dfrac{9}{2}\)
\(\Leftrightarrow\)\(x=2\)
\(-\dfrac{5}{8}.x=\dfrac{5}{6}\)
\(\Leftrightarrow\)\(-\dfrac{15}{24}.x=\dfrac{20}{24}\)
\(\Leftrightarrow\)\(x=-\dfrac{4}{3}\)
\(x+\dfrac{3}{13}=\dfrac{10}{13}\)
\(\Leftrightarrow\)\(x=\dfrac{10}{13}-\dfrac{3}{13}\)
\(\Leftrightarrow\)\(x=\dfrac{7}{13}\)