Đặt A = \(\frac{5}{2.1}+\frac{4}{1.11}+\frac{3}{11.2}+\frac{1}{2.15}+\frac{13}{15.4}\)

=> \(\frac{1}{7}A=\frac{5}{2.7}+\frac{4}{7.11}+\frac{3}{11.14}+\frac{1}{14.15}+\frac{13}{15.28}\)

=> \(\frac{1}{7}A=\frac{1}{2}-\frac{1}{7}+\frac{1}{7}-\frac{1}{11}+\frac{1}{11}-\frac{1}{14}+\frac{1}{14}-\frac{1}{15}+\frac{1}{15}-\frac{1}{28}\)

=> \(\frac{1}{7}A=\frac{1}{2}-\frac{1}{28}\)

=> \(\frac{1}{7}A=\frac{14}{28}-\frac{1}{28}\)

=>\(\frac{1}{7}A=\frac{13}{28}\)

=> A = \(\frac{13}{28}:\frac{1}{7}\)

=> A =\(\frac{13}{28}.7\)

=> A = \(\frac{13}{4}\)

a) xét tam giác ABC có 

A + B + C = 180

mà B=2C nên ta có A + 2C + C = 180

→ 3C =180 - 75 = 105

→C = 35 →B = 50