a.PTHH:H2+CuO----->Cu+H2O
b.\(n_{CuO}=\dfrac{m_{CuO}}{M_{CuO}}=\dfrac{4,8}{80}=0,06\left(mol\right)\)
Theo PTPỨ:1mol CuO----->1mol Cu
0,06mol CuO----->0,06mol Cu
\(m_{Cu}=n_{Cu}.M_{Cu}=0,06.64=3,84\left(g\right)\)
c.Theo PTPỨ:1mol CuO----->1mol H2O
0,06mol----->0,06mol H2O
\(m_{H_2O}=n_{H_2O}.M_{H_2O}=0,06.18=1,08\left(g\right)\)
d.Theo PTPỨ:nCuO=\(n_{H_2}\)=0,06(mol)
\(V_{H_2}=n_{H_2}.22,4=0,06.22,4=1,344\left(l\right)\)
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