Ngạc nhiên!!!!!!![]()
Ta có \(Ư\left(6\right)=\left\{\pm1;\pm2;\pm3;\pm6\right\}\)
\(\left(x-1\right)\in\left\{\pm1;\pm2;\pm3;\pm6\right\}\)
Ta có bảng sau;
| x-1 | 1 | -1 | 2 | -2 | 3 | -3 | 6 | -6 |
| x | 2 | 0 | 3 | -1 | 4 | -2 | 7 | -5 |
Vậy \(x\in\left\{-5;-2;-1;0;2;3;4;7\right\}\)