a)\(\frac{2}{3}\cdot x-\frac{3}{2}\cdot x=\frac{5}{12}\)
\(\left(\frac{2}{3}-\frac{3}{2}\right)\cdot x=\frac{5}{12}\)
\(-\frac{5}{6}\cdot x=\frac{5}{12}\)
\(x=\frac{\frac{5}{12}}{-\frac{5}{6}}\)
\(x=-\frac{1}{2}\)
b) \(\frac{7}{9}:\left(2+\frac{3}{4}\cdot x\right)+\frac{5}{9}=\frac{23}{27}\)
\(\frac{7}{9}:\left(2+\frac{3}{4}\cdot x\right)=\frac{23}{27}-\frac{5}{9}\)
\(\frac{7}{9}:\left(2+\frac{3}{4}\cdot x\right)=\frac{8}{27}\)
\(2+\frac{3}{4}\cdot x=\frac{7}{9}:\frac{8}{27}\)
\(2+\frac{3}{4}\cdot x=2\frac{5}{8}\)
\(\frac{3}{4}\cdot x=2\frac{5}{8}-2\)
\(\frac{3}{4}\cdot x=\frac{5}{8}\)
\(x=\frac{5}{8}:\frac{3}{4}\)
\(x=\frac{5}{6}\)
c) \(\frac{2}{5}+\frac{3}{5}\cdot\left(3x-3.7\right)=-\frac{53}{10}\)
\(\frac{3}{5}\cdot\left(3x-3.7\right)=-\frac{53}{10}-\frac{2}{5}\)
\(\frac{3}{5}\cdot\left(3x-3.7\right)=-5\frac{7}{10}\)
\(3x-3.7=-5\frac{7}{10}:\frac{3}{5}\)
\(3x-3.7=-9\frac{1}{2}\)
\(3x=-9\frac{1}{2}+3.7\)
\(3x=-5.8\)
\(x=\left(-5.8\right):3=-1,9\left(3\right)\)