\(bx^2=ay^{2^{ }}=\dfrac{x^2}{\dfrac{1}{b}}=\dfrac{y^2}{\dfrac{1}{a}}=\dfrac{x^2+y^2}{\dfrac{a+b}{ab}}=\dfrac{ab}{a+b}.\)

\(\Leftrightarrow\dfrac{x^2}{a}=\dfrac{1}{a+b}=\dfrac{y^2}{b}.\)

\(\dfrac{x^{2016}}{a^{1008}}+\dfrac{y^{2016}}{b^{1008}}=\left(\dfrac{x^2}{a}\right)^{1008}+\left(\dfrac{y^2}{b}\right)^{1008}=2.\left(\dfrac{1}{a+b}\right)^{1008}=\dfrac{2}{\left(a +b\right)^{1008}}\left(dpcm\right)\)

Đề ??

2^x+2^x+3=288

2^x.1+2^x.2³=288

2^x(1+2³)=288

2^x.9=288

2^x=288:9

2^x=32

2^x=2⁵

=> x=5

Vậy x=5

Bạn nào giỏi Tiếng Anh nhớ dạy mình nha! thanks...

Ta có : \(\sqrt{y\left(y+2\right)}=m\in N\)

\(\Leftrightarrow y^2+2y-m^2=0\Leftrightarrow\left(y+1\right)^2-m^2=1\)

\(\left(y+m+1\right)\left(y-m+1\right)=1\)

=> y = m =0

pt=> x = 1

Vậy x =1 ; y = 0