a) \(\dfrac{x-3}{5}+\dfrac{1+2x}{3}=6\)
\(\Leftrightarrow\dfrac{3.\left(x-3\right)}{15}+\dfrac{5.\left(1+2x\right)}{15}=\dfrac{90}{15}\)
\(\Rightarrow3x-9+5+10x=90\)
\(\Leftrightarrow13x=94\)
\(\Leftrightarrow x=\dfrac{94}{13}\)
b) \(\left(2x-3\right)\left(x^2+1\right)=0\)
\(\Leftrightarrow\left\{{}\begin{matrix}2x-3=0\\x^2-1=0\end{matrix}\right.\)
* \(2x-3=0\Leftrightarrow x=\dfrac{3}{2}\)
* \(x^2-1=0\Leftrightarrow x^2=-1\) ( vô lí )
c) \(\dfrac{2}{x+1}-\dfrac{1}{x-2}=\dfrac{3x-11}{\left(x+1\right)\left(x-2\right)}\) ĐKXĐ: \(x\ne-1;x\ne2\)
\(\Leftrightarrow\dfrac{2\left(x-2\right)}{\left(x+1\right)\left(x-2\right)}-\dfrac{x+1}{\left(x+1\right)\left(x-2\right)}=\dfrac{3x-11}{\left(x+1\right)\left(x-2\right)}\)
\(\Rightarrow2x-4-x-1=3x-11\)
\(\Leftrightarrow-2x=-6\)
\(\Leftrightarrow x=3\) ( nhận )
Bạn tụ kết luận nghiệm nha.