HOC24
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tìm tập xác định của hàm số
a) y = \(cot\left(2x+\dfrac{\pi}{4}\right)\)
b) y = \(cot\left(\dfrac{\pi}{3}-x\right)\)
a) y = \(tan\left(2x-\dfrac{\pi}{3}\right)\)
b) y = \(tan\left(3x-\dfrac{\pi}{4}\right)\)
1.cho cotx = -6 tính F = \(\dfrac{sinx-3cosx}{cosx+2sinx}\)
2. cho cotx = 1 tính I = \(\dfrac{sin^3x-4cos^3x}{sinx+3cosx}\)
3. cho cotx = 3 tính I = \(\dfrac{2sin^3x+cos^3x}{4sinx-6cosx}\)
cho tanx = -2 tính H = \(\dfrac{sin^3x+5cos^3x}{3sinx-2cosx}\)
1)cho tanx = 3 Tính B = \(\dfrac{2sinx-3cosx}{sinx+cox}\)
2) cho tanx = -1 Tính I = \(\dfrac{4sin^3x+cos^3x}{sinx+3cosx}\)
chứng minh đẳng thức lượng giác
a) \(\dfrac{1-cos^2\left(\dfrac{\pi}{2}-x\right)}{1-sin^2\left(\dfrac{\pi}{2}-x\right)}\)- cot\(\left(\dfrac{\pi}{2}-x\right)\).tan\(\left(\dfrac{\pi}{2}-x\right)\)= \(\dfrac{1}{sin^2x}\)
b) \(\left(\dfrac{1}{cos2x}+1\right)\).tan\(x\) = tan\(2x\)
a) 2.\(cot\left(\dfrac{\pi}{2}-x\right)\)+ tan\(\left(\pi-x\right)\)= tan\(x\)
b) sin\(\left(\dfrac{5\pi}{2}-x\right)\)+ cos \(\left(13\pi+x\right)\) - sin\(\left(x-5\pi\right)\) = sin\(x\)
a) 1 + \(tan^2\)x = \(\dfrac{1}{cos^2x}\)
b) tan\(x\) + cot\(x\) = \(\dfrac{1}{sinx.cosx}\)
modal verbs can/could/would/may/must/might/... -> modal verbs + be + past participle
1. i can answer the question
2. she would carry the box
3. you should open the window
4. we might play cards
5. you ought to wash the car
6. he must fill in the form
7. could you feed the dog ?
8. could Jenny lock the door ?