\(\left(2x+1\right)^2=49\)

\(\Rightarrow\left(2x+1\right)^2=\left(\pm7\right)^2\)

TH1: \(2x+1=7\Rightarrow2x=6\Rightarrow x=3\)

TH2: \(2x+1=-7\Rightarrow2x=-8\Rightarrow x=-4\)

\(4:\dfrac{6}{5}=4\times\dfrac{5}{6}=\dfrac{4\times5}{6}=\dfrac{20}{6}=\dfrac{20:2}{6:2}=\dfrac{10}{3}\)

1 tấn = 1000 kg

12 yến = 120 kg

1 tấn 12 yến = 1000 + 120 = 1120 kg

1. will call

2. will rain

3. will be

4. won't visit

5. will be

Chọn phương án A.

\(1-\dfrac{1}{2}-\dfrac{1}{4}-\dfrac{1}{6}=\dfrac{12}{12}-\dfrac{6}{12}-\dfrac{3}{12}-\dfrac{2}{12}=\dfrac{1}{12}\)

Sửa lại câu 1:

\(\left|x+2\right|=\left|-12+2\right|=\left|-10\right|=10\)