Độ dài đáy là \(6\times10=60\left(dm\right)\)

Diện tích : \(6\times60=360\left(dm^2\right)\)

\(3^x.3^{x+1}.3^{x+3}=3^{x+x+1+x+3}=3^{3x+4}\)

\(=265\times\left(236+265-1\right)\\ =265\times500\\ =132500\)

\(=3.\left(12+35.98\right)\\ =3.\left(12+3430\right)\\ =3.3442\\ =10326\)

:D 

\(40x=\dfrac{x}{\dfrac{1}{40}} \)

Ta có

\(\dfrac{x}{\dfrac{1}{40}}=x:\dfrac{1}{40}=x\times\dfrac{40}{1}=40x\)

\(\dfrac{2x}{3}=\dfrac{x}{\dfrac{3}{2}}\\ \Rightarrow\dfrac{3}{2}\times2x=3x\\ \Rightarrow\dfrac{6x}{2}=3x\\ \Rightarrow3x=3x\)

\(\Rightarrow\dfrac{2x}{3}=\dfrac{x}{\dfrac{3}{2}}\)

\(B=\dfrac{\dfrac{2}{3}\times\left(\dfrac{17}{3}-\dfrac{4}{13}\right)+\dfrac{7}{3}}{\dfrac{9}{2}-\dfrac{9}{4}-\dfrac{9}{5}}=\dfrac{\dfrac{2}{3}\times1+\dfrac{7}{3}}{\dfrac{9.10-9.5-9.4}{20}}\\ =\dfrac{\dfrac{2}{3}+\dfrac{7}{3}}{\dfrac{90-45-36}{20}}=\dfrac{\dfrac{9}{3}}{\dfrac{9}{20}}=\dfrac{9}{3}\times\dfrac{20}{9}=\dfrac{20}{3}\)

\(đk:\left\{{}\begin{matrix}x\ne4\\x\ne-4\end{matrix}\right.\\ 5-\dfrac{96}{x^2-16}=\dfrac{2x-1}{x+4}+\dfrac{3x-1}{x-4}\\ \Rightarrow5.\left(x^2-16\right)-96=\left(2x-1\right)\left(x-4\right)+\left(3x-1\right)\left(x+4\right)\\ \Rightarrow5x^2-80-96=2x^2-x-8x+4+3x^2-x+12x-4\\ \Rightarrow-176=2x\\ \Rightarrow x=-88\left(t/mđk\right)\)