Bài 3 tìm x

a) (x-1)(x-5) 3=0

b) 3x^2+7x=10

Bài 1: Rút gọn

a) (x+3)^2+(x-3)^2+2(x^2-9)

bài 1 : Rút gọn biểu thức

a) 3x.(x-2)-5x(1-x)-8(x^2-3)

b) (7x-3) (2x+1) - (5x-2) (x+4)-9x^2 + 17x

\(\left(\dfrac{1}{3}+\dfrac{12}{67}+\dfrac{13}{41}\right)-\left(\dfrac{79}{67}-\dfrac{28}{41}\right)\)

\(\left(\dfrac{15}{4}-5x\right)\cdot\left(9x^2-4\right)=0\)

\(\sqrt{x-2}+\dfrac{1}{3}=1\)

\(\left(0.25\right)^{10}\cdot4^{10}+\sqrt{5^2-3^2}\)

\(\dfrac{5}{20}+\dfrac{18}{11}-25\%-\left(\dfrac{18}{11}-\dfrac{4}{9}\right)\)

        chứng minh Ax//BC

e)\(\dfrac{2-x}{4}=\dfrac{3x-1}{-3}\)\(\)        f)\(\dfrac{x}{7}=\dfrac{x+16}{35}\) 

\(\dfrac{-16}{x+1}=\dfrac{x+1}{-4}\)