đù kinh đấy có luôn

\(10\cdot x+65=125\)

           \(10x=125-65\)

           \(10x=60\)

               \(x=60:10\)

               \(x=6.\)

\(Vậy...\)

\(a.=x\left(x^3-2x^3+x-2\right)=x\left(x-2\right)\left(x^2+1\right).\)

\(b.=\left(x^4+x^3\right)+\left(-8x-8\right)=x^3\left(x+1\right)-8\left(x+1\right)\)

\(=\left(x+1\right)\left(x^3-8\right)=\left(x+1\right)\left(x-2\right)\left(x^2+2x+2^2\right)\)

\(=\left(x+1\right)\left(x-2\right)\left(x^2+2x+4\right).\)

\(c.=\left(x^2+xy\right)+\left(-x-y\right)=x\left(x+y\right)-\left(x+y\right)\)\(=\left(x+y\right)\left(x-1\right).\)

\(e.=xy+2y-3x-3\cdot2=xy+2y-3x-6\)

\(=\left(xy+2y\right)+\left(-3x-6\right)=y\left(x+2\right)-3\left(x+2\right)\)

\(=\left(x+2\right)\left(y-3\right).\)

\(a.3^4.\)

\(b.=2\cdot4\cdot8^4=8\cdot8^4=8^5.\)

\(c.=1000\cdot1000=1000^2.\)

\(d.=x^4.\)

\(e.=125\cdot125=125^2.\)

\(d.=256\cdot256=256^2.\)

ko đăng tào lao