He can't help me __with__ my homework

Tham Khảo

- Do khí hậu nước ta có sự phân hoá Bắc - Nam, phân hoá theo độ cao.

- Do khí hậu có sự phân hoá theo mùa.

\(\dfrac{5}{8}x-0,75+\dfrac{3}{20}x=\dfrac{35}{2}\\ \dfrac{31}{40}x-0,75=\dfrac{35}{2}\\ \dfrac{31}{40}x=\dfrac{35}{2}+\dfrac{3}{4}\\ \dfrac{31}{40}x=\dfrac{73}{4}\\ x=\dfrac{73}{4}:\dfrac{31}{40}\\ x=\dfrac{730}{31}\)

\(=-772-228=-1000\)

\(b,=4\sqrt{2}+4\sqrt{3}-2\sqrt{6}-6-4\sqrt{3}+2\sqrt{6}-4\sqrt{2}=-6\\ d,=5-2\sqrt{15}+3+2\sqrt{15}=8\\ f,=3-4\sqrt{15}+20-4\left(3+2\sqrt{15}+5\right)=23-4\sqrt{15}-32-8\sqrt{15}=-9-12\sqrt{15}\)

\(a,=2.3-2\sqrt{3}.\sqrt{15}+6\sqrt{5}=6-6\sqrt{5}+6\sqrt{5}=6\\ c,=10-\sqrt{15}-2\sqrt{10}+\sqrt{6}+2\sqrt{10}-\sqrt{6}=10-\sqrt{15}\\ e,=18-6\sqrt{6}+9-2+6\sqrt{6}+27=52\)

a,  

\(BaO+H_2O-->Ba\left(OH\right)_2\\ P_2O_5+H_2O-->2H_3PO_4\)

\(K_2O+H_2O-->2KOH\\ SO_2+H_2O-->H_2SO_3\)

b, 

\(K_2O+H_2SO_4-->K_2SO_4+H_2O\\ BaO+H_2SO_4-->BaSO_4+H_2O\)

c, \(SO_2+KOH--->KHSO_3\\ 6KOH+P_2O_5-->2K_3PO_4+3H_2O\)

\(a,A=x^3+3x^2+3x+1+5=\left(x+1\right)^3+5=\left(19+1\right)^3+5=\left(20\right)^3+5=8000+5=8005\\ b,B=x^3-3x^2+3x-1+1=\left(x-1\right)^3+1=\left(11-1\right)^3+1=\left(10\right)^3+1=1000+1=1001\)

\(=\left(1,24-0,24\right)\left(1,24+0,24\right)=1.\left(1.48\right)=1,48\)

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